Yes but you don't need the same number in order compare plane trips vs car trips. All you need is a good sample size to provide a confidence level that is for you to define.
All this can be worked out mathematically.
For example if you want to know, with 99% confidence the outcome of flipping a coin you don't have to flip it millions of times. All you need is 664 flips.
This is based upon this formula
To determine the sample size needed to estimate the probability of heads vs. tails for a coin flip with a 99% confidence level, we can use the formula for sample size in estimating a population proportion:
View attachment 222431
Where:
( n ) = sample size (number of coin flips)
( Z ) = Z-score for the confidence level (for 99% confidence, Z≈2.576Z \approx 2.576Z \approx 2.576
)
( p ) = estimated proportion (for a fair coin, p=0.5p = 0.5p = 0.5
)
( E ) = margin of error (desired precision, e.g., ±5% or 0.05)